思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
Some games might even find a way to make both types of backend operation part of their design. Imagine an always-online MMO style game where server-authoritative data is critical. Now imagine a standalone offline side-story that uses the same gameplay mechanics and systems. The same C# code powers both modes, but is used in drastically different ways.，这一点在搜狗输入法2026中也有详细论述
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The right light makes such a difference!。关于这个话题，WPS官方版本下载提供了深入分析